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4x^2-97x+570=0
a = 4; b = -97; c = +570;
Δ = b2-4ac
Δ = -972-4·4·570
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-97)-17}{2*4}=\frac{80}{8} =10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-97)+17}{2*4}=\frac{114}{8} =14+1/4 $
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